Triangle $ABC$ has $AC=3$, $BC=4$, and $AB=5$. Point $D$ is on $\overline{AB}$, and $\overline{CD}$ bisects the right angle. The inscribed circles of $△ADC$ and $△BCD$ have radii $r_a$ and $r_b$, respectively. What is $r_a+r_b$?