SAT Math Practice Question #35674 - SATify | SATify
#35674
quadratic equations
equations
hard
120 sec
The solutions to x2+4x+1=0 are r and s, where r<s. The solutions to x2+10x+13=0 are t and u, where t<u. The solutions to x2+14x+c=0, where c is a constant, are r+t and s+u. What is the value of c?
• Up to 5 characters (6 if negative). Only numbers, decimal (.), fraction (/), negative (-). • Fractions must be in lowest terms. • Mixed numbers must be converted to improper fractions.