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SAT Math Practice Question #28297 - SATify | SATify
#28297
complex numbers
functions
Calculus
hard
150 sec
A function
f
is defined by
f
(
z
)
=
z
2
. How many values of
z
satisfy both
∣
z
∣
=
1
and
f
(
z
)
=
z
?
A.
0
B.
1
C.
2
D.
4
E.
8
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