A coin is biased in such a way that on each toss the probability of heads is $\frac{1}{4}$ and the probability of tails is $\frac{3}{4}$. The outcomes of the tosses are independent. A player has the choice of playing Game A or Game B. In Game A she tosses the coin three times and wins if exactly two outcomes are heads. In Game B she tosses the coin four times and wins if the first two outcomes are different and the last two outcomes are different. How do the chances of winning Game A compare to the chances of winning Game B?