The kinetic energy $K$ of an object is given by the formula $K=\frac{1}{2}m{v}^2$, where $m$ is the mass and $v$ is the speed. Object A has a mass of $m_A$ and a speed of $v_A$. Object B has a mass of $2m_A$ and a kinetic energy four times that of Object A. What is the ratio of the speed of Object B to the speed of Object A, that is, $\frac{v_B}{v_A}$?