SAT Math Practice Question #27619 - SATify | SATify
#27619
combinatorics
counting
hard
150 sec
There are 4 red pegs, 3 blue pegs, 2 green pegs, and 1 yellow peg to be placed on a triangular peg board with 4 rows. In how many ways can the pegs be placed so that no (horizontal) row or (vertical) column contains two pegs of the same color?