The number of distinct real solutions to a quadratic equation of the form $a{x}^2+bx+c=0$ can be determined by the discriminant, $b^2-4ac$.

• If $b^2-4ac>0$, there are two distinct real solutions.
• If $b^2-4ac=0$, there is exactly one distinct real solution.
• If $b^2-4ac<0$, there are no real solutions.

Based on this, how many distinct real solutions does the equation $x^2-6x+10=0$ have?