In triangle $ABC$, point $D$ divides side $\overline{AC}$ so that $AD:DC=1:3$. Let $E$ divide $\overline{BD}$ so that $BE:ED=1:2$. Let $F$ be the point of intersection of line $AE$ and line $BC$. Given that the area of $△ABC$ is $360$, what is the area of $△EBF$?